1/8^3x^2-3x=64^9x-21

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Solution for 1/8^3x^2-3x=64^9x-21 equation: 



1/8^3x^2-3x=64^9x-21

We move all terms to the left:

1/8^3x^2-3x-(64^9x-21)=0



Domain of the equation: 8^3x^2!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-3x+1/8^3x^2-(64^9x-21)=0

We get rid of parentheses

-3x+1/8^3x^2-64^9x+21=0

We multiply all the terms by the denominator


-3x*8^3x^2-64^9x*8^3x^2+21*8^3x^2+1=0

Wy multiply elements

-24x^4-512x^12+168x^3+1=0

We do not support expression: x^4

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